# Ring Frame: Gearing Diagram, Calculation of Spindle Speed & Front Roller Speed

Last Updated on 03/08/2022

Experiment name:
Study on the gearing diagram, calculation of spindle speed and front roller speed of the ring frame.

Ring frame:
The ring frame is normally fed with roving from a large bobbin, and delivers yarn to a smaller one. The ring frame consists of a large number of spindles. One traveler and spindle co-operate with a bobbin, to twist and wind the yarn from a drafting system as shown in Fig.

The objectives of the ring frame are given below:

1. To draft the input material to the linear density required in the final yarn,
2. To insert the required amount of twist, and
3. To wind the yarn onto a package which is suitable for handling, storage and transport and is capable of being unwound at high speed in subsequent processing.

Objectives:

1. To know about the different parts of the ring frame.
2. To know about the function of the different parts of the ring frame machine.
3. To know about the driving mechanism of the spindle in ring frame.
4. To calculate the front roller delivery of the machine.
5. To study the machine in order to improve our technical knowledge.

Gearing diagram of ring frame:

Machine specification:

1. RPM of the motor                                           = 1440
2. Diameter of the motor pulley                          = 5″
3. Diameter of the tin cylinder pulley                 = 10.5″
4. Diameter of the tin cylinder                            = 10″
5. Diameter of the wharve                                  = 1.125″
6. No of teeth of lower grip wheel                     = 26T
7. No of teeth of upper grip wheel                     = 46T
8. No of teeth of fibre wheel                              = 42T
9. No of teeth of twist carrier wheel                   = 86T
10. No of teeth of twist wheel                              = 48T
11. No of teeth of front roller driving wheel        = 98T
12. Diameter of front roller                                   = 1″

Calculation:

Spindle Speed = 1440 x (5”/10.5”) x (10”/1.125”) = 6095.24

Front roller delivery = 1440 x (5”/10.5”) x (26/46) x (42/86) x (48/98) x π x 1” = 323.56 inch/min

Result:

Spindle Speed = 6095.24 rpm

Front roller delivery = 323.56 inch/min

Conclusion:
Our teacher and lab assistants are very much helpful to us. Their well teaching and instruction help us greatly to understand this practical. I think this practical will be very helpful in my future career.

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